1/7x^2-4=5/7x^2

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Solution for 1/7x^2-4=5/7x^2 equation: 


x in (-oo:+oo)

(1/7)*x^2-4 = (5/7)*x^2 // - (5/7)*x^2

(1/7)*x^2-((5/7)*x^2)-4 = 0

(1/7)*x^2+(-5/7)*x^2-4 = 0

-4/7*x^2 = 4 // : -4/7

x^2 = -7

x belongs to the empty set

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